If the lines $\frac{x-1}{-3}=\frac{y-2}{2k}=\frac{z-3}{2}$ and $\frac{x-1}{3k}=\frac{y-5}{1}=\frac{z-6}{-5}$ are perpendicular to each other,then $k$ is
- A$\frac{7}{10}$
- B$\frac{10}{7}$
- C$\frac{-7}{10}$
- D$\frac{-10}{7}$
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