If the lines $\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-1}{4}$ and $\frac{x-3}{-1}=\frac{y-k}{2}=\frac{z}{1}$ intersect,then $k$ is equal to

  • A
    $\frac{-5}{6}$
  • B
    $\frac{5}{6}$
  • C
    $\frac{6}{5}$
  • D
    $\frac{-6}{5}$

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