If the letters of the word $REGULATIONS$ are arranged in such a way that the relative positions of the letters of the word $GULATIONS$ remain the same,then the probability that there are exactly $4$ letters between $R$ and $E$ is

  • A
    $\frac{3}{55}$
  • B
    $\frac{6}{55}$
  • C
    $\frac{9}{55}$
  • D
    $\frac{7}{55}$

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