If the length of the tangent from $(h, k)$ to the circle $x^2+y^2=16$ is twice the length of the tangent from the same point to the circle $x^2+y^2+2x+2y=0$,then:

  • A
    $h^2+k^2+4h+4k+16=0$
  • B
    $h^2+k^2+3h+3k=0$
  • C
    $3h^2+3k^2+8h+8k+16=0$
  • D
    $3h^2+3k^2+4h+4k+16=0$

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For the circle $C$ with the equation $x^2+y^2-16x-12y+64=0$,match the List-$I$ with the List-$II$ given below.
List-$I$List-$II$
$(i)$ The equation of the polar of $(-5, 1)$ with respect to $C$$(A)$ $y = 0$
$(ii)$ The equation of the tangent at $(8, 0)$ to $C$$(B)$ $y = 6$
$(iii)$ The equation of the normal at $(2, 6)$ to $C$$(C)$ $x + y = 7$
$(iv)$ The equation of the diameter of $C$ through $(8, 12)$$(D)$ $13x + 5y = 98$
$(E)$ $x = 8$

The correct match is:

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