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(B) The power $P$ of a heater is given by the formula $P = \frac{V^2}{R}$,where $V$ is the voltage and $R$ is the resistance of the filament.Since the

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increase by about $11\%$

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(B) The power $P$ of a heater is given by the formula $P = \frac{V^2}{R}$,where $V$ is the voltage and $R$ is the resistance of the filament.Since the resistance $R$ is directly proportional to the length $L$ of the filament $(R = \rho \frac{L}{A})$,reducing the length by $10\%$ means the new length $L' = 0.9L$.Therefore,the new resistance $R'$ becomes $R' = 0.9R$.The new power $P'$ is given by $P' = \frac{V^2}{R'} = \frac{V^2}{0.9R} = \frac{1}{0.9} P \approx 1.111P$.This represents an increase of approximately $11\%$ in the power of the heater.

If the length of the filament of a heater is reduced by $10\%$,the power of the heater will

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