If the length of a closed organ pipe is $1 \ m$ and the velocity of sound is $330 \ m/s$,then the frequency for the second note (first overtone) is:
- A$4 \times \frac{330}{4} \ Hz$
- B$3 \times \frac{330}{4} \ Hz$
- C$2 \times \frac{330}{4} \ Hz$
- D$2 \times \frac{4}{330} \ Hz$
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