If the length of a DNA molecule is 1.1 metres | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The distance between two consecutive base pairs in a $DNA$ molecule is $0.34 	ext{ nm}$ or $0.34 	imes 10^{-9} 	ext{ m}$.Given the total length

Vedclass · Accepted Answer

$3.3 	imes 10^{9} 	ext{ bp}$

Vedclass · Answer

(D) The distance between two consecutive base pairs in a $DNA$ molecule is $0.34 	ext{ nm}$ or $0.34 	imes 10^{-9} 	ext{ m}$.Given the total length of the $DNA$ molecule is $1.1 	ext{ m}$.The number of base pairs is calculated by dividing the total length by the distance between two consecutive base pairs:$	ext{Number of base pairs} = \frac{	ext{Total length}}{	ext{Distance between two base pairs}}$$	ext{Number of base pairs} = \frac{1.1 	ext{ m}}{0.34 	imes 10^{-9} 	ext{ m}}$$	ext{Number of base pairs} \approx 3.235 	imes 10^{9} 	ext{ bp}$.Rounding this to the nearest option,we get $3.3 	imes 10^{9} 	ext{ bp}$.

If the length of a $DNA$ molecule is $1.1$ metres,what will be the approximate number of base pairs?

Similar Questions

What structure is formed when two polynucleotide chains in $DNA$ are coiled together?

In which of the following are split genes found?

The pitch of the $B-DNA$ is

$DNA$ differs from $RNA$ because:

If the sequence of one strand of $DNA$ is $5^{\prime}-ATGCATCG-3^{\prime}$,find the sequence of the complementary strand in the $5^{\prime} \rightarrow 3^{\prime}$ direction.

Vedclass Test Series

Exam Paper Generator

Online Exam Module