If the Least Common Multiple (LCM) of (12, 15 | vedclass

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Question

(A) To find the $LCM$ of $12, 15,$ and $21$,we first find their prime factorizations:
$12 = 2^2 	imes 3^1$
$15 = 3^1 	imes 5^1$
$21 = 3^1 	imes

Vedclass · Accepted Answer

$-40$

Vedclass · Answer

(A) To find the $LCM$ of $12, 15,$ and $21$,we first find their prime factorizations:
$12 = 2^2 	imes 3^1$
$15 = 3^1 	imes 5^1$
$21 = 3^1 	imes 7^1$
The $LCM$ is the product of the highest powers of all prime factors involved:
$LCM(12, 15, 21) = 2^2 	imes 3^1 	imes 5^1 	imes 7^1 = 4 	imes 3 	imes 5 	imes 7 = 420$
Given the equation: $LCM(12, 15, 21) = 500 + 2x$
$420 = 500 + 2x$
$2x = 420 - 500$
$2x = -80$
$x = -40$

If the Least Common Multiple $(LCM)$ of $(12, 15, 21) = 500 + 2x$,then $x = $ . . . . . .

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