If the ionization energy of $He^{+}$ is $8.68 \times 10^{-18} \ J$,then the energy of $Be^{3+}$ ion in the second orbit is:- ($Z$ of $Be = 4$)

  • A
    $-4.9 \times 10^{-18} \ J$
  • B
    $-44.1 \times 10^{-18} \ J$
  • C
    $-11.025 \times 10^{-18} \ J$
  • D
    $-8.68 \times 10^{-18} \ J$

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