Easy
If the impurity in a metal has a greater affinity for oxygen and is more easily oxidised than the metal,then the purification of metal may be carried out by
- ACupellation
- BElectrorefining
- CZone refining
- DPoling
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Similar Questions
During the refining of copper,the methane gas produced acts as a reducing agent. What is its specific role?
Medium
View SolutionMatch the following:
List-$I$ (Process) List-$II$ (Metal) $A$. Hall-Heroult process $I$. $Ti$ $B$. Mond process $II$. $In$ $C$. van-Arkel process $III$. $Al$ $D$. Zone refining process $IV$. $Ni$
The correct answer is:
| List-$I$ (Process) | List-$II$ (Metal) |
|---|---|
| $A$. Hall-Heroult process | $I$. $Ti$ |
| $B$. Mond process | $II$. $In$ |
| $C$. van-Arkel process | $III$. $Al$ |
| $D$. Zone refining process | $IV$. $Ni$ |
The correct answer is:
Which one of the following methods can be used to obtain highly pure metal which is liquid at room temperature?
Name the common elements present in the anode mud in electrolytic refining of copper. Why are they so present?
Medium
View SolutionMatch the following List-$I$ (Method) with List-$II$ (Metal refined):
List-$I$ (Method) List-$II$ (Metal refined) $(A)$ Zone refining $(I)$ $Sn$ $(B)$ Liquation $(II)$ $In$ $(C)$ Vapour phase refining $(III)$ $Zn$ $(D)$ Distillation $(IV)$ $Zr$ - $(V)$ $Al$
The correct answer is:
| List-$I$ (Method) | List-$II$ (Metal refined) |
|---|---|
| $(A)$ Zone refining | $(I)$ $Sn$ |
| $(B)$ Liquation | $(II)$ $In$ |
| $(C)$ Vapour phase refining | $(III)$ $Zn$ |
| $(D)$ Distillation | $(IV)$ $Zr$ |
| - | $(V)$ $Al$ |
The correct answer is:
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