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(B) The bandwidth required for a single $AM$ broadcast station is given by twice the maximum modulating frequency.Bandwidth per station $= 2 	imes f_

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$9$

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(B) The bandwidth required for a single $AM$ broadcast station is given by twice the maximum modulating frequency.Bandwidth per station $= 2 	imes f_m = 2 	imes 5\, kHz = 10\, kHz$.To find the number of stations that can be accommodated in a total bandwidth of $90\, kHz$,we divide the total bandwidth by the bandwidth per station.Number of stations $= \frac{	ext{Total Bandwidth}}{	ext{Bandwidth per station}} = \frac{90\, kHz}{10\, kHz} = 9$.Therefore,$9$ stations can be accommodated.

If the highest frequency modulating a carrier is $5\, kHz$,then the number of $AM$ broadcast stations accommodated in a $90\, kHz$ bandwidth are ....... .

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