If the function $f(x) = \frac{e^{x}(e^{\tan x-x}-1)+\log_{e}(\sec x+\tan x)-x}{\tan x-x}$ is continuous at $x=0$,then the value of $f(0)$ is equal to

  • A
    $2$
  • B
    $\frac{2}{3}$
  • C
    $\frac{1}{2}$
  • D
    $\frac{3}{2}$

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