If the frequency of light in a photoelectric | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The maximum kinetic energy for the photoelectrons is given by Einstein's photoelectric equation:$K_{\max} = h
u - \phi$where $
u$ is the frequen

Vedclass · Accepted Answer

become more than double

Vedclass · Answer

(C) The maximum kinetic energy for the photoelectrons is given by Einstein's photoelectric equation:$K_{\max} = h
u - \phi$where $
u$ is the frequency of incident light and $\phi$ is the work function of the metal.Since $K_{\max} = eV_0$,we have:$eV_0 = h
u - \phi$ ......... $(1)$When the frequency is doubled $(u' = 2
u)$,the new stopping potential $V_0'$ is:$eV_0' = h(2
u) - \phi = 2h
u - \phi$We can rewrite this as:$eV_0' = 2(h
u - \phi) + \phi$Since $eV_0 = h
u - \phi$,we have $h
u = eV_0 + \phi$. Substituting this into the equation for $eV_0'$:$eV_0' = 2(eV_0 + \phi) - \phi = 2eV_0 + 2\phi - \phi = 2eV_0 + \phi$Dividing by $e$,we get:$V_0' = 2V_0 + \frac{\phi}{e}$Since $\phi > 0$,it is clear that $V_0' > 2V_0$. Therefore,the stopping potential becomes more than double.

If the frequency of light in a photoelectric experiment is doubled,the stopping potential will

Similar Questions

Which scientist proposed the theory of continuity of germplasm?

The solution of the differential equation $\frac{dy}{dx} = \frac{x-2y+1}{2x-4y}$ is

The energy $(E)$,angular momentum $(L)$,and universal gravitational constant $(G)$ are chosen as fundamental quantities. The dimensions of the universal gravitational constant in the dimensional formula of Planck's constant $(h)$ is

$A$ marine cartilaginous fish that can produce electric current is

If the pair of straight lines given by $A x^2+2 H x y+B y^2=0$,where $(H^2 > A B)$,forms an equilateral triangle with the line $a x+b y+c=0$,then $(A+3 B)(3 A+B)=$ (in $H^2$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module