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(C) The circuit acts as a half-wave rectifier. When the input voltage is $+10 V$,the $P$-terminal of the diode is at a higher potential than the $N$-t

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(C) The circuit acts as a half-wave rectifier. When the input voltage is $+10 V$,the $P$-terminal of the diode is at a higher potential than the $N$-terminal,making the diode forward-biased. In this state,the diode conducts,and the output voltage across $R_L$ is $+10 V$. When the input voltage is $-10 V$,the $P$-terminal is at a lower potential than the $N$-terminal,making the diode reverse-biased. In this state,the diode does not conduct,and the output voltage across $R_L$ is $0 V$. Therefore,the output signal is a pulse that remains at $+10 V$ when the input is $+10 V$ and drops to $0 V$ when the input is $-10 V$.

If the following input signal is sent through a $PN$-junction diode,then the output signal across $R_L$ will be:

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