If the far point of a short-sighted person is | vedclass

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(D) person with short-sightedness (myopia) cannot see distant objects clearly because the image forms in front of the retina. To correct this, a conca

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$-0.25 \ D$

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(D) person with short-sightedness (myopia) cannot see distant objects clearly because the image forms in front of the retina. To correct this, a concave lens is used.For a person to see objects at infinity $(u = \infty)$, the lens must form a virtual image at the person's far point $(v = -400 \ cm = -4 \ m)$.Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.Substituting the values: $\frac{1}{f} = \frac{1}{-4} - \frac{1}{\infty} = -0.25 \ m^{-1}$.Since power $P = \frac{1}{f(	ext{in meters})}$, we get $P = -0.25 \ D$.

If the far point of a short-sighted person is $400 \ cm$, then the power of the lens required to enable him to see very distant objects clearly is

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