If the engine of a long train moving with constant acceleration crosses a tree with velocity $u$ and the last compartment of the train crosses the same tree with velocity $v$,then the velocity with which the middle compartment crosses the same tree is

  • A
    $\frac{(v+u)}{2}$
  • B
    $\frac{2uv}{(u+v)}$
  • C
    $\sqrt{\frac{v^2+u^2}{2}}$
  • D
    $\sqrt{2(u^2+v^2)}$

Explore More

Similar Questions

$A$ particle starts its motion from rest under the action of a constant force. If the distance covered in the first $10 \ s$ is $S_1$ and that covered in the first $20 \ s$ is $S_2$,then:

The velocity of a car travelling on a straight road is $3.6 \ km/h$ at an instant of time. Now,travelling with uniform acceleration for $10 \ s$,the velocity becomes exactly double. If the wheel radius of the car is $25 \ cm$,then which of the following is the closest to the number of revolutions that the wheel makes during this $10 \ s$?

The velocity of an object is given by $v = kt$,where $k = 2 \, m/s^2$. What distance (in $m$) will it cover in the first $3 \, s$?

Difficult
View Solution

$A$ rifle bullet loses $1/20^{th}$ of its velocity in passing through a wooden plank. The least number of planks required to stop the bullet is :-

Difficult
View Solution

The distance $x$ covered in time $t$ by a body having initial velocity $u$ and having constant acceleration $a$ is given by $x=ut+\frac{1}{2}at^2$. This result follows from

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo