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(B) The energy of the emitted photon is given by the relation $E = \frac{hc}{\lambda}$.Given the energy gap $E = 1.9 \ eV$.We know that $hc \approx 12

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Red

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(B) The energy of the emitted photon is given by the relation $E = \frac{hc}{\lambda}$.Given the energy gap $E = 1.9 \ eV$.We know that $hc \approx 1240 \ eV \cdot nm$.Therefore,the wavelength $\lambda = \frac{hc}{E} = \frac{1240 \ eV \cdot nm}{1.9 \ eV} \approx 652.6 \ nm$.The wavelength range for red light is approximately $620 \ nm$ to $750 \ nm$.Since $652.6 \ nm$ falls within this range,the color of the light emitted by the $LED$ is red.

If the energy gap of a semiconductor used for the fabrication of an $LED$ is nearly $1.9 \ eV$,then the color of the light emitted by the $LED$ is

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