If the domain and range of f(x){ = ^{9 - | vedclass

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Question

Clearly $9-x \geq 0, x-1 \geq 0 $ and $ 9-x-(x-1) \geq 0$

$\Rightarrow 1 \leq \mathrm{x} \leq 5, \quad \mathrm{x} \in \mathrm{I}$

$	herefore m=

Vedclass · Accepted Answer

$m = n + 1$

Vedclass · Answer

Clearly $9-x \geq 0, x-1 \geq 0 $ and $ 9-x-(x-1) \geq 0$

$\Rightarrow 1 \leq \mathrm{x} \leq 5, \quad \mathrm{x} \in \mathrm{I}$

$	herefore m=5$

Range of $f({m{x}}) = \,\left\{ {^8{{m{C}}_0},{\,^7}{{m{C}}_1},{\,^6}{{m{C}}_2},{\,^5}{{m{C}}_3},{\,^4}{{m{C}}_4}} ight\}$

or $\{1,7,15,10\}$

$	herefore n=4$

If the domain and range of $f(x){ = ^{9 - x}}{C_{x - 1}}$ contains $m$ and $n$ elements respectively, then

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