If the distance between two consecutive base | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The length of $DNA$ is calculated by multiplying the distance between two consecutive base pairs by the total number of base pairs.Given:Distance

Vedclass · Accepted Answer

$2.2 \, meters$

Vedclass · Answer

(D) The length of $DNA$ is calculated by multiplying the distance between two consecutive base pairs by the total number of base pairs.Given:Distance between two base pairs = $0.34 \, nm = 0.34 	imes 10^{-9} \, m$.Total number of base pairs = $6.6 	imes 10^{9} \, bp$.Length of $DNA$ = $(	ext{Distance between two base pairs}) 	imes (	ext{Total number of base pairs})$.Length of $DNA$ = $(0.34 	imes 10^{-9} \, m) 	imes (6.6 	imes 10^{9} \, bp)$.Length of $DNA$ = $0.34 	imes 6.6 \, m = 2.244 \, m$.Therefore,the length of the $DNA$ is approximately $2.2 \, meters$.

If the distance between two consecutive base pairs is $0.34 \, nm$ and the total number of base pairs of a $DNA$ double helix in a typical mammalian cell is $6.6 \times 10^{9} \, bp$,then the length of the $DNA$ is approximately:

Similar Questions

The supercoiled structure of the eukaryotic chromosome is explained by which model?

What is the length of a $DNA$ molecule consisting of three turns?

The reason for the double helical structure of $DNA$ is the operation of

Which of the following statements is true for $DNA$?

Which one of the following pairs of nitrogenous bases of nucleic acids is wrongly matched with the category mentioned against it?

Vedclass Test Series

Exam Paper Generator

Online Exam Module