If the distance between Na^{+} and Cl^{-} ion | vedclass

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(A) In an $NaCl$ crystal, which has a face-centered cubic $(fcc)$ structure, the distance between the $Na^{+}$ and $Cl^{-}$ ions is equal to the sum o

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$2a$

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(A) In an $NaCl$ crystal, which has a face-centered cubic $(fcc)$ structure, the distance between the $Na^{+}$ and $Cl^{-}$ ions is equal to the sum of their ionic radii $(r_{Na^+} + r_{Cl^-})$.This distance is equal to half of the edge length of the unit cell $(d = \frac{a}{2})$.Given that the distance $r_{Na^+} + r_{Cl^-} = a \, pm$, we have $a = \frac{	ext{edge length}}{2}$.Therefore, the length of the cell edge is $2 	imes a = 2a$.

If the distance between $Na^{+}$ and $Cl^{-}$ ions in $NaCl$ crystal is $a \, pm$, what is the length of the cell edge?

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