If the difference of the roots of $x^2 - px + 8 = 0$ is $2$,then the value of $p$ is

  • A
    $ \pm 2$
  • B
    $ \pm 4$
  • C
    $ \pm 6$
  • D
    $ \pm 8$

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Let $\alpha$ and $\beta$ be the roots of the quadratic equation $a x^2+b x+c=0$. Match the conditions in List-$I$ with the corresponding relations in List-$II$.
List-$I$List-$II$
$(i) \alpha = \beta$$(A) (ac^2)^{1/3} + (a^2c)^{1/3} + b = 0$
$(ii) \alpha = 2\beta$$(B) 2b^2 = 9ac$
$(iii) \alpha = 3\beta$$(C) b^2 = 6ac$
$(iv) \alpha = \beta^2$$(D) 3b^2 = 16ac$
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