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(B) The power dissipated by a resistor is given by the formula $P = I^2 R$,where $I$ is the current and $R$ is the resistance.Taking the logarithmic d

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increases approximately by $6 \%$

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(B) The power dissipated by a resistor is given by the formula $P = I^2 R$,where $I$ is the current and $R$ is the resistance.Taking the logarithmic derivative of the expression,we get $\frac{\Delta P}{P} = 2 \frac{\Delta I}{I}$.To find the percentage change,we multiply both sides by $100$:$\frac{\Delta P}{P} 	imes 100 = 2 	imes \left( \frac{\Delta I}{I} 	imes 100 ight)$.Given that the percentage change in current $\frac{\Delta I}{I} 	imes 100 = 3 \%$.Therefore,the percentage change in power dissipation is $2 	imes 3 \% = 6 \%$.

If the current through a resistor in a circuit increases by $3 \%$,then the power dissipated by the resistor

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