If the coordinates of the position of an obje | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: Focal length $f = -40 \, cm$ (concave mirror),object distance $u = -60 \, cm$,and object height $h_o = 6 \, cm$.Using the mirror formula: $

Vedclass · Accepted Answer

$(-120 \, cm, -12 \, cm)$

Vedclass · Answer

(B) Given: Focal length $f = -40 \, cm$ (concave mirror),object distance $u = -60 \, cm$,and object height $h_o = 6 \, cm$.Using the mirror formula: $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$$\frac{1}{-40} = \frac{1}{v} + \frac{1}{-60}$$\frac{1}{v} = \frac{1}{60} - \frac{1}{40} = \frac{2 - 3}{120} = -\frac{1}{120}$So,$v = -120 \, cm$.The magnification $m$ is given by $m = -\frac{v}{u} = -\frac{-120}{-60} = -2$.The height of the image $h_i = m 	imes h_o = -2 	imes 6 \, cm = -12 \, cm$.Since the image is formed at $v = -120 \, cm$ and its height is $-12 \, cm$,the coordinates of the image are $(-120 \, cm, -12 \, cm)$.

If the coordinates of the position of an object are $(-60 \, cm, 6 \, cm)$,then the coordinates of the image will be:

Similar Questions

Write the mirror equation for a spherical mirror.

At what distance in front of a concave mirror of focal length $30\; cm$,should an object be placed (in $cm$) so that its real image of size three times that of the object is obtained?

What will be the height of the image when an object of height $2 \ mm$ is placed on the principal axis of a convex mirror (of radius of curvature $40 \ cm$) at a distance of $20 \ cm$ from the mirror?

Consider the following statements regarding an object placed between the pole and the focus of a concave mirror: $I$. The image is real. $II$. The image is magnified. $III$. The image is erect. Which of the following is correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module