(D) Given the thermo emf equation: $V = 10 \times 10^{-6} t - \frac{1}{40} \times 10^{-6} t^2$. To find the neutral temperature $(t_n)$,we differentia

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(D) Given the thermo emf equation: $V = 10 \times 10^{-6} t - \frac{1}{40} \times 10^{-6} t^2$. To find the neutral temperature $(t_n)$,we differentiate $V$ with respect to $t$ and set it to zero: $\frac{dV}{dt} = 10 \times 10^{-6} - \frac{2}{40} \times 10^{-6} t = 0$. $10 \times 10^{-6} = \frac{1}{20} \times 10^{-6} t_n$. $t_n = 200^{\circ} C$. To find the maximum thermo emf $(V_{\max})$,we substitute $t_n = 200^{\circ} C$ into the original equation: $V_{\max} = 10 \times 10^{-6} (200) - \frac{1}{40} \times 10^{-6} (200)^2$. $V_{\max} = 2 \times 10^{-3} - \frac{40000}{40} \times 10^{-6} = 2 \times 10^{-3} - 1 \times 10^{-3} = 1 \times 10^{-3} \text{ V} = 1 \text{ mV}$.

Class 12 Physics Current Electricity Mix Examples-Current Electricity

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If the cold junction is held at $0^{\circ} C$,the thermo emf $V$ of a thermocouple varies as $V = 10 \times 10^{-6} t - \frac{1}{40} \times 10^{-6} t^2$,where $t$ is the temperature of the hot junction in $^{\circ} C$. The neutral temperature and the maximum value of thermo emf are respectively:

TS EAMCET 2006 All TS EAMCET

AP EAMCET 2006 All AP EAMCET

A
$200^{\circ} C ; 2 \text{ mV}$
B
$400^{\circ} C ; 2 \text{ mV}$
C
$100^{\circ} C ; 1 \text{ mV}$
D
$200^{\circ} C ; 1 \text{ mV}$

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The two ends of a conductor are connected to a cell having an $e.m.f. \ E$ and some internal resistance. Starting from the midpoint $P$ of the conductor,moving in the direction of the current,and returning to point $P$,which of the following graphs best represents the potential $V$ versus the distance $x$ covered along the path?

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In the circuit shown,$E, F, G$,and $H$ are cells of e.m.f. $2\,V, 1\,V, 3\,V$,and $1\,V$ respectively,and their internal resistances are $2\,\Omega, 1\,\Omega, 3\,\Omega$,and $1\,\Omega$ respectively.

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Find the percentage error in the reading of the voltmeter shown in the circuit. (in $\%$)

Medium

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In a $Cu-Fe$ thermocouple,what is the nature of the current flow at the temperature of inversion?

Medium

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Match the List-$I$ with the List-$II$ from the combination shown. In the left side (List-$I$) there are four different conditions and in the right side (List-$II$), there are ratios of heat produced in each resistance for each condition:
List-$I$ List-$II$
$(I)$ Two wires of same resistance are connected in series and same current is passed through them $(A)$ $1:2$
$(II)$ Two wires of resistance $R$ and $2R$ $\Omega$ are connected in series and same $P.D.$ is applied across them $(B)$ $4:1$
$(III)$ Two wires of same resistance are connected in parallel and same current is flowing through them $(C)$ $1:1$
$(IV)$ Two wires of resistances in the ratio $1:2$ are connected in parallel and same $P.D.$ is applied across them $(D)$ $2:1$

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List-$I$	List-$II$
$(I)$ Two wires of same resistance are connected in series and same current is passed through them	$(A)$ $1:2$
$(II)$ Two wires of resistance $R$ and $2R$ $\Omega$ are connected in series and same $P.D.$ is applied across them	$(B)$ $4:1$
$(III)$ Two wires of same resistance are connected in parallel and same current is flowing through them	$(C)$ $1:1$
$(IV)$ Two wires of resistances in the ratio $1:2$ are connected in parallel and same $P.D.$ is applied across them	$(D)$ $2:1$

If the cold junction is held at $0^{\circ} C$,the thermo emf $V$ of a thermocouple varies as $V = 10 \times 10^{-6} t - \frac{1}{40} \times 10^{-6} t^2$,where $t$ is the temperature of the hot junction in $^{\circ} C$. The neutral temperature and the maximum value of thermo emf are respectively:

Similar Questions

In the circuit shown,$E, F, G$,and $H$ are cells of e.m.f. $2\,V, 1\,V, 3\,V$,and $1\,V$ respectively,and their internal resistances are $2\,\Omega, 1\,\Omega, 3\,\Omega$,and $1\,\Omega$ respectively.

Find the percentage error in the reading of the voltmeter shown in the circuit. (in $\%$)

In a $Cu-Fe$ thermocouple,what is the nature of the current flow at the temperature of inversion?

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