If the axis of a parabola is horizontal and i | vedclass

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(D) The general equation of a parabola with a horizontal axis is $x = ay^2 + by + c$.Since the parabola passes through $(0, 0)$,we have $0 = a(0)^2 +

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None of these

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(D) The general equation of a parabola with a horizontal axis is $x = ay^2 + by + c$.Since the parabola passes through $(0, 0)$,we have $0 = a(0)^2 + b(0) + c$,which implies $c = 0$.So,the equation is $x = ay^2 + by$.Using the point $(0, -1)$,we get $0 = a(-1)^2 + b(-1)$,which means $a - b = 0$,so $a = b$.Using the point $(6, 1)$,we get $6 = a(1)^2 + b(1)$,which means $a + b = 6$.Substituting $a = b$ into $a + b = 6$,we get $2a = 6$,so $a = 3$ and $b = 3$.The equation is $x = 3y^2 + 3y$,or $3y^2 + 3y - x = 0$.Comparing this with the given options,none of the provided equations match the result.

If the axis of a parabola is horizontal and it passes through the points $(0, 0), (0, -1)$ and $(6, 1)$,then its equation is

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