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(D) The element with atomic number $26$ is Iron $(Fe)$.Its electronic configuration is $[Ar] 3d^6 4s^2$.The divalent ion $Fe^{2+}$ has the configurati

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$4.90$

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(D) The element with atomic number $26$ is Iron $(Fe)$.Its electronic configuration is $[Ar] 3d^6 4s^2$.The divalent ion $Fe^{2+}$ has the configuration $[Ar] 3d^6$.In the $3d$ subshell, there are $4$ unpaired electrons.The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$, where $n$ is the number of unpaired electrons.Substituting $n = 4$, we get $\mu = \sqrt{4(4+2)} = \sqrt{24} \approx 4.90 \ BM$.

If the atomic number of an element is $26$, then the magnetic moment of its divalent aqueous ion is . . . . . . $BM$.

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