If 10 volumes of dihydrogen gas react with 5 | vedclass

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(B) The balanced chemical equation for the reaction is:$2H_{2(g)} + O_{2(g)} \longrightarrow 2H_{2}O_{(g)}$According to Gay-Lussac's Law of Gaseous Vo

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$10$ volumes

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(B) The balanced chemical equation for the reaction is:$2H_{2(g)} + O_{2(g)} \longrightarrow 2H_{2}O_{(g)}$According to Gay-Lussac's Law of Gaseous Volumes, $2$ volumes of $H_{2}$ react with $1$ volume of $O_{2}$ to produce $2$ volumes of $H_{2}O$ vapour.Given $10$ volumes of $H_{2}$ and $5$ volumes of $O_{2}$, the ratio is $10:5$ or $2:1$, which matches the stoichiometric ratio.Therefore, $10$ volumes of $H_{2}$ will react completely with $5$ volumes of $O_{2}$ to produce $10$ volumes of water vapour.

If $10$ volumes of dihydrogen gas react with $5$ volumes of dioxygen gas, how many volumes of water vapour would be produced?

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