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Question

If resistance does not vary with temperature $P_{consumed} = $${\left( {\frac{{{V_A}}}{{{V_R}}}} ight)^2} 	imes {P_R} = {\left( {\frac{{110}}{{220}

Vedclass · Accepted Answer

$> 25\, W$

Vedclass · Answer

If resistance does not vary with temperature $P_{consumed} = $${\left( {\frac{{{V_A}}}{{{V_R}}}} ight)^2} 	imes {P_R} = {\left( {\frac{{110}}{{220}}} ight)^2} 	imes 100 = 25\,W$. But in second cases resistance decreases so consumed power will be more than $25\, W$

If resistance of the filament increases with temperature, what will be power dissipated in a $220\, V- 100\, W$ lamp when connected to $110\, V$ power supply

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