(D) Case $I$: Shunt resistance $R_1$ for a galvanometer $G$ to pass $\frac{1}{n}$ of the main current $i$ is given by $R_1 = \frac{G}{n-1}$.Here,$n =

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(D) Case $I$: Shunt resistance $R_1$ for a galvanometer $G$ to pass $\frac{1}{n}$ of the main current $i$ is given by $R_1 = \frac{G}{n-1}$.Here,$n = 51$,so $R_1 = \frac{G}{51-1} = \frac{G}{50}$.Case $II$: Series resistance $R_2$ for a galvanometer $G$ to measure $\frac{1}{m}$ of the main voltage $V$ is given by $R_2 = G(m-1)$.Here,$m = 11$,so $R_2 = G(11-1) = 10G$.Now,calculating the ratio $\frac{R_2}{R_1}$:$\frac{R_2}{R_1} = \frac{10G}{G/50} = 10G \times \frac{50}{G} = 500$.

Class 12 Physics Moving Charges and Magnetism The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

Medium

If only $\frac{1}{51}$ of the main current is to be passed through a galvanometer,then the shunt required is $R_1$. If only $\frac{1}{11}$ of the main voltage is to be developed across the galvanometer,then the resistance required is $R_2$. Find the ratio $\frac{R_2}{R_1}$.

AP EAMCET 2019 All AP EAMCET

A
$\frac{1}{500}$
B
$\frac{50}{9}$
C
$\frac{500}{3}$
D
$500$

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Moving Charges and Magnetism

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The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

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If only $\frac{1}{51}$ of the main current is to be passed through a galvanometer,then the shunt required is $R_1$. If only $\frac{1}{11}$ of the main voltage is to be developed across the galvanometer,then the resistance required is $R_2$. Find the ratio $\frac{R_2}{R_1}$.

Similar Questions

$A$ galvanometer of resistance $50 \Omega$ gives a full-scale deflection for a current of $5 \times 10^{-4} \text{ A}$. The resistance that should be connected in series with the galvanometer to read $3 \text{ V}$ is: (in $Omega$)

The resistance of an ideal voltmeter is . . . . . . .

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