If Mohan has 3 tickets of a lottery containin | vedclass

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Question

(a) Mohan can gets one prize, $2$ prizes or $3$ prizes and his chance of failure means he get no prize.

Number of total ways $ = {}^{12}{C_3} = 220

Vedclass · Accepted Answer

$\frac{{34}}{{55}}$

Vedclass · Answer

(a) Mohan can gets one prize, $2$ prizes or $3$ prizes and his chance of failure means he get no prize.

Number of total ways $ = {}^{12}{C_3} = 220$

Favourable number of ways to be failure $ = {}^9{C_3} = 84$

Hence required probability $ = 1 - \frac{{84}}{{220}} = \frac{{34}}{{55}}.$

If Mohan has $3$ tickets of a lottery containing $3$ prizes and $9$ blanks, then his chance of winning prize are

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