If in an examination 20 % students failed in | vedclass

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(D) Let $H$ be the set of students who failed in Hindi and $E$ be the set of students who failed in English.Given: $n(H) = 20 \%$,$n(E) = 25 \%$,and $

Vedclass · Accepted Answer

$38$

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(D) Let $H$ be the set of students who failed in Hindi and $E$ be the set of students who failed in English.Given: $n(H) = 20 \%$,$n(E) = 25 \%$,and $n(H \cap E) = 7 \%$.We need to find the percentage of students who failed in at least one subject,which is $n(H \cup E)$.Using the formula: $n(H \cup E) = n(H) + n(E) - n(H \cap E)$.$n(H \cup E) = 20 \% + 25 \% - 7 \% = 38 \%$.Therefore,$38 \%$ of students failed in at least one subject.

If in an examination $20 \%$ students failed in Hindi,$25 \%$ failed in English,and $7 \%$ failed in both subjects,then what is the percentage of students who failed in at least one of the subjects (in $\%$)?

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