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(D) The velocity of sound $v$ in a resonance tube is given by the formula $v = 2n(l_2 - l_1)$,where $n$ is the frequency of the tuning fork,$l_1$ is t

Vedclass · Accepted Answer

$80$

Vedclass · Answer

(D) The velocity of sound $v$ in a resonance tube is given by the formula $v = 2n(l_2 - l_1)$,where $n$ is the frequency of the tuning fork,$l_1$ is the first resonance length,and $l_2$ is the second resonance length.Given: $n = 512 \ Hz$,$l_1 = 30.7 \ cm$,$l_2 = 63.2 \ cm$.Substituting the values:$v = 2 	imes 512 	imes (63.2 - 30.7) \ cm/s$$v = 1024 	imes 32.5 \ cm/s = 33280 \ cm/s$.The actual speed of sound is given as $v_0 = 332 \ m/s = 33200 \ cm/s$.The error in the velocity of sound is $\Delta v = |v - v_0| = |33280 - 33200| \ cm/s = 80 \ cm/s$.

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