If in a certain number of years, ₹ 3000 amoun | vedclass

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Question

(b) Let, $r \%$ be the rate and $n$ years be the time.

Then, $4320=3000\left(1+\frac{r}{100}ight)^{n}$

$	herefore \quad\left(1+\frac{r}{100}\

Vedclass · Accepted Answer

$3600$

Vedclass · Answer

(b) Let, $r \%$ be the rate and $n$ years be the time.

Then, $4320=3000\left(1+\frac{r}{100}ight)^{n}$

$	herefore \quad\left(1+\frac{r}{100}ight)^{n}=\frac{4320}{3000}=1.44$

$	herefore \quad\left(1+\frac{r}{100}ight)^{n / 2}=\sqrt{1.44}=1.2$

$	herefore \operatorname{In} \frac{n}{2}$ years, ₹3000 will amount to

$3000\left(1+\frac{r}{100}ight)^{n / 2}=3000 	imes 1.2$

$=₹ 3600$

If in a certain number of years, ₹ $3000$ amounts to ₹ $4320$ at a compound interest, in half that time ₹ $3000$ will amount to (In ₹)

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