If four persons are chosen at random from a group of $3$ men, $2$ women and $4 $ children. Then the probability that exactly two of them are children, is
If four persons are chosen at random from a group of $3$ men, $2$ women and $4 $ children. Then the probability that exactly two of them are children, is
- A
$\frac{{10}}{{21}}$
- B
$\frac{8}{{63}}$
- C
$\frac{5}{{21}}$
- D
$\frac{9}{{21}}$
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