If an electromagnetic wave is propagating in | vedclass

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(A) For an electromagnetic wave propagating in the $+x$ direction,the electric field vector $\vec{E}$ oscillates in the $y$-direction and the magnetic

Vedclass · Accepted Answer

$E_y = E_0 \sin(kx - \omega t)$,$B_z = B_0 \sin(kx - \omega t)$

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(A) For an electromagnetic wave propagating in the $+x$ direction,the electric field vector $\vec{E}$ oscillates in the $y$-direction and the magnetic field vector $\vec{B}$ oscillates in the $z$-direction.The general form of a plane electromagnetic wave traveling in the $+x$ direction is given by the wave functions:$E_y = E_0 \sin(kx - \omega t)$$B_z = B_0 \sin(kx - \omega t)$Here,$E_0$ and $B_0$ are the amplitudes of the electric and magnetic fields,$k$ is the wave number,and $\omega$ is the angular frequency. These fields are in phase and satisfy the relation $E_0 = cB_0$,where $c$ is the speed of light.

If an electromagnetic wave is propagating in the $x$-direction and the electric and magnetic fields are in the $y$ and $z$-directions respectively,then write the equations for $E_y$ and $B_z$.

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