If current in an electric bulb changes by 1%, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The power $P$ consumed by an electric bulb is given by the formula $P = i^2R$,where $i$ is the current and $R$ is the resistance of the bulb.Assum

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) The power $P$ consumed by an electric bulb is given by the formula $P = i^2R$,where $i$ is the current and $R$ is the resistance of the bulb.Assuming the resistance $R$ remains constant,we can use the method of relative errors:$\frac{\Delta P}{P} = 2 \frac{\Delta i}{i}$.To find the percentage change,we multiply both sides by $100$:$\left( \frac{\Delta P}{P} 	imes 100 ight) = 2 	imes \left( \frac{\Delta i}{i} 	imes 100 ight)$.Given that the percentage change in current is $1\%$,we have:$\% 	ext{ change in power} = 2 	imes 1\% = 2\%$.Therefore,the power will change by $2\%$.

If current in an electric bulb changes by $1\%$,then the power will change by ............ $\%$

Similar Questions

Two electric bulbs have tungsten filaments of the same length. If one of them is rated $60\ W$ and the other $100\ W$,then:

Why is electric power transmitted at very high voltage over long distances to reduce Ohmic loss?

If a $2\, kW$ boiler is used everyday for $1$ hour, then the electrical energy consumed by the boiler in thirty days is .......... $units$.

The material of a fuse wire should have:

$A$ constant potential difference is applied to the ends of a graphite rod, whose resistance decreases with a rise in temperature. The rod can be $(1)$ covered with asbestos or $(2)$ left open to the atmosphere. Answer for the steady state.

Vedclass Test Series

Exam Paper Generator

Online Exam Module