If any two letters in the word 'PRISON' have | vedclass

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(C) To find the alpha-pairs in the word $'PRISON'$,we count the letters between each pair in the word and compare it with the number of letters betwee

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) To find the alpha-pairs in the word $'PRISON'$,we count the letters between each pair in the word and compare it with the number of letters between them in the English alphabet:$1$. $P$ and $R$: In the word,there is $1$ letter $(R)$. In the alphabet,there is $1$ letter $(Q)$. This is a pair $(P, R)$.$2$. $P$ and $O$: In the word,there are $4$ letters $(R, I, S, O)$. In the alphabet,there are $14$ letters. Not a pair.$3$. $R$ and $O$: In the word,there are $3$ letters $(I, S, O)$. In the alphabet,there are $2$ letters $(P, Q)$. Not a pair.$4$. $I$ and $N$: In the word,there are $2$ letters $(S, O)$. In the alphabet,there are $4$ letters $(J, K, L, M)$. Not a pair.Checking forward and backward:- $P$ to $R$: $1$ letter between ($Q$ in alphabet,$R$ in word). Pair found.- $I$ to $N$: No pair.- $S$ to $O$: No pair.- $N$ to $O$: $N$ and $O$ are consecutive in the alphabet and in the word. Pair found.Thus,there are $2$ such pairs: $(P, R)$ and $(N, O)$.

If any two letters in the word $'PRISON'$ have as many letters between them in the word as there are in the English alphabet,they form an alpha-pair. How many such alpha-pairs are there in the word $'PRISON'$?

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