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Question

(D) The electronic configuration of the $C_{2}$ molecule is $\sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, \pi 2p_{y}^{2} = \pi

Vedclass · Accepted Answer

$\sigma_{2p}$

Vedclass · Answer

(D) The electronic configuration of the $C_{2}$ molecule is $\sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, \pi 2p_{y}^{2} = \pi 2p_{x}^{2}$.According to the molecular orbital theory for $C_{2}$,the next available molecular orbital after the $\pi 2p$ orbitals is the $\sigma 2p_{z}$ orbital.Therefore,if an extra electron is added to the $C_{2}$ molecule,it will occupy the $\sigma 2p_{z}$ molecular orbital.Thus,the correct option is $D$.

If an extra electron is added to the hypothetical molecule $C_{2}$,this extra electron will occupy the molecular orbital.

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