If all the letters of the word MOST are permu | vedclass

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(C) The letters of the word $MOST$ are $M, O, S, T$. All are distinct. Total number of permutations = $4! = 24$.To find the dictionary order,we arrang

Vedclass · Accepted Answer

$12$

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(C) The letters of the word $MOST$ are $M, O, S, T$. All are distinct. Total number of permutations = $4! = 24$.To find the dictionary order,we arrange the letters alphabetically: $M, O, S, T$.$1$. Words starting with $M$: $3! = 6$ words.$2$. Words starting with $O$: $3! = 6$ words.$3$. Words starting with $S$: - $SM..$: $2! = 2$ words.- $SO..$: $2! = 2$ words.- $STMO$: $1$ word.- $STOM$: $1$ word.Rank of $MOST$: Words starting with $M$ are $1$ to $6$. So,$MOST$ is the $6^{th}$ word.Rank of $STOM$: - Words starting with $M$: $6$ words.- Words starting with $O$: $6$ words.- Words starting with $S$:- $SM..$: $2$ words.- $SO..$: $2$ words.- $STMO$: $1$ word.- $STOM$: $1$ word.Total rank of $STOM = 6 + 6 + 2 + 2 + 1 + 1 = 18$.The rank of $STOM$ counted from the rank of $MOST$ is $18 - 6 = 12$.

If all the letters of the word $MOST$ are permuted and the words (with or without meaning) thus obtained are arranged in the dictionary order,then the rank of the word $STOM$ when counted from the rank of the word $MOST$ is:

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