If a system absorbs 30 kJ of heat and perfor | vedclass

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(A) According to the first law of thermodynamics,the change in internal energy $(\Delta U)$ is given by the equation: $\Delta U = q + w$. Here,the sys

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$18$

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(A) According to the first law of thermodynamics,the change in internal energy $(\Delta U)$ is given by the equation: $\Delta U = q + w$. Here,the system absorbs heat,so $q = +30 \ kJ$. The system performs work on the surroundings,so $w = -12 \ kJ$. Substituting these values: $\Delta U = 30 \ kJ + (-12 \ kJ) = 18 \ kJ$. Therefore,the increase in internal energy is $18 \ kJ$.

If a system absorbs $30 \ kJ$ of heat and performs $12 \ kJ$ of work on the surroundings,what is the increase in internal energy of the system (in $kJ$)?

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