If a star emitting light of wavelength 5000,m | vedclass

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(C) The Doppler shift in wavelength for light is given by the formula: $\Delta\lambda = \lambda \cdot \frac{v}{c}$,where $\lambda$ is the original wav

Vedclass · Accepted Answer

$25$

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(C) The Doppler shift in wavelength for light is given by the formula: $\Delta\lambda = \lambda \cdot \frac{v}{c}$,where $\lambda$ is the original wavelength,$v$ is the velocity of the source relative to the observer,and $c$ is the speed of light.Given:$\lambda = 5000\,\mathring{A}$$v = 1.5 	imes 10^6\,	ext{m/s}$$c = 3 	imes 10^8\,	ext{m/s}$Substituting these values into the formula:$\Delta\lambda = 5000 	imes \frac{1.5 	imes 10^6}{3 	imes 10^8}$$\Delta\lambda = 5000 	imes \frac{1.5}{300}$$\Delta\lambda = 5000 	imes 0.005$$\Delta\lambda = 25\,\mathring{A}$Since the star is moving towards the Earth,there is a blue shift (a decrease in wavelength).

If a star emitting light of wavelength $5000\,\mathring{A}$ is moving towards Earth with a velocity of $1.5 \times 10^6\,\text{m/s}$,then the shift in the wavelength due to Doppler's effect will be......$\mathring{A}$

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