If a person can throw a stone to a maximum he | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When a stone is thrown vertically upward with initial velocity $u$,the maximum height reached is given by the formula:$h = \frac{u^2}{2g}$From thi

Vedclass · Accepted Answer

$2h$

Vedclass · Answer

(C) When a stone is thrown vertically upward with initial velocity $u$,the maximum height reached is given by the formula:$h = \frac{u^2}{2g}$From this,we can express the square of the initial velocity as:$u^2 = 2gh$When the same stone is thrown horizontally (as a projectile) to achieve the maximum horizontal range $R_{\max}$,the angle of projection should be $	heta = 45^{\circ}$. The formula for maximum horizontal range is:$R_{\max} = \frac{u^2}{g}$Substituting the value of $u^2$ from the first equation into the second equation:$R_{\max} = \frac{2gh}{g}$$R_{\max} = 2h$Thus,the maximum horizontal distance the person can throw the stone is $2h$.

If a person can throw a stone to a maximum height of $h$ meters vertically,then the maximum distance through which it can be thrown horizontally by the same person is

Similar Questions

$A$ particle of mass $M$ is moving in a horizontal circle of radius $R$ with uniform speed $v$. When the particle moves from one point to a diametrically opposite point,its

$A$ particle moves along a circle of radius $R$ with kinetic energy $K = as^2$,where $s$ is the distance traveled. What is the net force acting on the particle?

Two bodies of mass $10 \, kg$ and $5 \, kg$ are moving in concentric orbits of radii $R$ and $r$ such that their periods are the same. What is the ratio of their centripetal accelerations?

Vedclass Test Series

Exam Paper Generator

Online Exam Module