If A had worked alone, he would have taken 63 | vedclass

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(C) Given:$A$ alone takes $63 \, 	ext{hours}$.$A + B$ together take $36 \, 	ext{hours}$.Let the total work be the Least Common Multiple $(LCM)$ of $

Vedclass · Accepted Answer

$2550$

Vedclass · Answer

(C) Given:$A$ alone takes $63 \, 	ext{hours}$.$A + B$ together take $36 \, 	ext{hours}$.Let the total work be the Least Common Multiple $(LCM)$ of $63$ and $36$, which is $252 \, 	ext{units}$.Efficiency of $A = \frac{252}{63} = 4 \, 	ext{units/hour}$.Efficiency of $(A + B) = \frac{252}{36} = 7 \, 	ext{units/hour}$.Efficiency of $B = (A + B) - A = 7 - 4 = 3 \, 	ext{units/hour}$.The ratio of work done (and thus the ratio of wages) by $A$ and $B$ is $4:3$.Total parts $= 4 + 3 = 7$.$B$'s share $= \frac{3}{7} 	imes 5950 = 3 	imes 850 = Rs. 2550$.

If $A$ had worked alone, he would have taken $63 \, \text{hours}$ to complete the task. If $A$ and $B$ work together, they finish the task in $36 \, \text{hours}$. If they are paid $Rs. 5,950$ for the work, what is $B$'s share?

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