If a galaxy is at a distance of 430 million l | vedclass

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(B) Hubble's Law is given by the formula $v = H 	imes r$,where $v$ is the recession velocity,$H$ is the Hubble constant,and $r$ is the distance.Given

Vedclass · Accepted Answer

$15$

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(B) Hubble's Law is given by the formula $v = H 	imes r$,where $v$ is the recession velocity,$H$ is the Hubble constant,and $r$ is the distance.Given:Velocity $v = 6.48 	imes 10^6 m s^{-1} = 6480 km s^{-1}$.Distance $r = 430$ million light years.We need to find $H$ in units of $km s^{-1}$ per million light years.$H = \frac{v}{r} = \frac{6480 km s^{-1}}{430 	ext{ million light years}}$.$H \approx 15.07 km s^{-1} 	ext{ per million light year}$.Rounding to the nearest integer,we get $15 km s^{-1}$ per million light year.Therefore,the correct option is $B$.

If a galaxy is at a distance of $430$ million light years from us,what is the Hubble's constant in $km s^{-1}$ per million light years? Its speed is $6.48 \times 10^6 m s^{-1}$.

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