If a dice is thrown twice,the probability of | vedclass

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Question

(A) When a dice is thrown once,the probability of getting a $4$ is $p = \frac{1}{6}$.The probability of not getting a $4$ is $q = 1 - p = 1 - \frac{1}

Vedclass · Accepted Answer

$\frac{11}{36}$

Vedclass · Answer

(A) When a dice is thrown once,the probability of getting a $4$ is $p = \frac{1}{6}$.The probability of not getting a $4$ is $q = 1 - p = 1 - \frac{1}{6} = \frac{5}{6}$.For two throws,the probability of getting $4$ at least once is given by $1 - P(	ext{getting no } 4 	ext{ in two throws})$.The probability of not getting a $4$ in two throws is $q^2 = (\frac{5}{6})^2 = \frac{25}{36}$.Therefore,the required probability is $1 - \frac{25}{36} = \frac{36 - 25}{36} = \frac{11}{36}$.

If a dice is thrown twice,the probability of occurrence of $4$ at least once is

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