If a cycle wheel of radius 4 , m completes on | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: Radius $r = 4 \, m$,Time period $T = 2 \, s$.Frequency $n = \frac{1}{T} = \frac{1}{2} \, Hz$.Since the wheel is rotating,the acceleration o

Vedclass · Accepted Answer

$4{\pi ^2} \, m/s^2$

Vedclass · Answer

(C) Given: Radius $r = 4 \, m$,Time period $T = 2 \, s$.Frequency $n = \frac{1}{T} = \frac{1}{2} \, Hz$.Since the wheel is rotating,the acceleration of a point on the rim is the centripetal acceleration $a_c$.The formula for centripetal acceleration is $a_c = \omega^2 r$,where $\omega = 2\pi n$.Substituting the values: $\omega = 2\pi 	imes \frac{1}{2} = \pi \, rad/s$.Therefore,$a_c = (\pi)^2 	imes 4 = 4\pi^2 \, m/s^2$.

If a cycle wheel of radius $4 \, m$ completes one revolution in two seconds,then the acceleration of a point on the rim of the cycle wheel will be:

Similar Questions

$A$ particle moving with uniform speed in a circular path maintains:

Assertion $(A)$: The speed of a body in uniform circular motion is constant.
Reason $(R)$: In uniform circular motion,the acceleration of the body is constant.

For a particle moving in a circle with a constant angular velocity,which of the following statements is incorrect?

In uniform circular motion,

Angular speed of the hour hand of a clock in degrees per second is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module