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(D) The current $I$ is given by $I = nAev_d$,where $n$ is the number density,$A$ is the cross-sectional area,$e$ is the charge of an electron,and $v_d

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$455 	imes 10^{-11} \ Ns$

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(D) The current $I$ is given by $I = nAev_d$,where $n$ is the number density,$A$ is the cross-sectional area,$e$ is the charge of an electron,and $v_d$ is the drift velocity.The total number of electrons $N$ in a conductor of length $L$ and volume $V = AL$ is $N = nAL$.From the current formula,$nA = I / (ev_d)$.Substituting this into the expression for $N$,we get $N = (I / (ev_d)) 	imes L = IL / (ev_d)$.The total momentum $P$ of the electrons is $P = N 	imes m_e 	imes v_d$,where $m_e$ is the mass of an electron.Substituting $N$ into the momentum equation: $P = (IL / (ev_d)) 	imes m_e 	imes v_d = (I 	imes L 	imes m_e) / e$.Given $I = 80 \ A$,$L = 10 \ m$,$m_e = 9.1 	imes 10^{-31} \ kg$,and $e = 1.6 	imes 10^{-19} \ C$.$P = (80 	imes 10 	imes 9.1 	imes 10^{-31}) / (1.6 	imes 10^{-19})$.$P = (728 	imes 10^{-30}) / (1.6 	imes 10^{-19}) = 455 	imes 10^{-11} \ Ns$.

If a current of $80 \ A$ is passing through a straight conductor of length $10 \ m$,then the total momentum of electrons in the conductor is (mass of electron $= 9.1 \times 10^{-31} \ kg$ and charge of electron $= 1.6 \times 10^{-19} \ C$).

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