If a colour blind man marries a normal vision | vedclass

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Question

(B) Colour blindness is an $X$-linked recessive disorder.The genotype of a colour blind man is $X^cY$ and that of a normal visioned woman is $X^CX^C$.

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(B) Colour blindness is an $X$-linked recessive disorder.The genotype of a colour blind man is $X^cY$ and that of a normal visioned woman is $X^CX^C$.When they cross,the offspring genotypes are:$X^cY 	imes X^CX^C ightarrow X^CX^c$ (Carrier daughter),$X^CX^c$ (Carrier daughter),$X^CY$ (Normal son),$X^CY$ (Normal son).All daughters are carriers (phenotypically normal) and all sons have normal vision.Therefore,$0\%$ of the offspring will show colour blindness phenotypically.

Column $I$	Column $II$
$(a)$ Sickle cell anaemia	$(x)$ Homogentisic acid
$(b)$ Alkaptonuria	$(y)$ Melanin pigments are absent
$(c)$ Albinism	$(z)$ More amount of phenylalanine
$(d)$ Phenylketonuria	$(w)$ Defective haemoglobin

If a colour blind man marries a normal visioned woman,what is the percentage of offsprings showing colour blindness phenotypically (in $\%$)?

Similar Questions

$A$ couple,both carriers for the gene of sickle cell anaemia,are planning to get married. What are the chances of them having an anaemic child (in $\%$)?

Which symbol is used in pedigree analysis to represent a carrier offspring?

Match the columns:

Column $I$ Column $II$

$(a)$ Sickle cell anaemia $(x)$ Homogentisic acid

$(b)$ Alkaptonuria $(y)$ Melanin pigments are absent

$(c)$ Albinism $(z)$ More amount of phenylalanine

$(d)$ Phenylketonuria $(w)$ Defective haemoglobin

If an albino man marries a normal woman and $50$ offspring are albino and $50$ are normal,the woman is:

The daughter born to a haemophilic father and a normal mother could be:

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