If a charge on the body is 1 nC,then how man | vedclass

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(B) The quantization of charge is given by the formula $q = n e$,where $q$ is the total charge,$n$ is the number of electrons,and $e$ is the elementar

Vedclass · Accepted Answer

$6.25 	imes 10^{9}$

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(B) The quantization of charge is given by the formula $q = n e$,where $q$ is the total charge,$n$ is the number of electrons,and $e$ is the elementary charge $(e \approx 1.6 	imes 10^{-19} \ C)$.To find the number of electrons $n$,we rearrange the formula: $n = \frac{q}{e}$.Given the charge $q = 1 \ nC = 1 	imes 10^{-9} \ C$.Substituting the values: $n = \frac{1 	imes 10^{-9} \ C}{1.6 	imes 10^{-19} \ C}$.$n = \frac{1}{1.6} 	imes 10^{10} = 0.625 	imes 10^{10} = 6.25 	imes 10^{9}$.Therefore,the number of electrons present on the body is $6.25 	imes 10^{9}$.

If a charge on the body is $1 \ nC$,then how many electrons are present on the body?

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