If a bar magnet of pole strength m and magnet | vedclass

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(C) Initial pole strength $= m$ and magnetic moment $= M = m 	imes (2l)$.When a magnet is cut $n$ times parallel to its axis,the pole strength of eac

Vedclass · Accepted Answer

$\frac{m}{6}, \frac{M}{24}$

Vedclass · Answer

(C) Initial pole strength $= m$ and magnetic moment $= M = m 	imes (2l)$.When a magnet is cut $n$ times parallel to its axis,the pole strength of each piece becomes $\frac{m}{n+1}$. Here,$n=5$,so the new pole strength $m' = \frac{m}{5+1} = \frac{m}{6}$.When a magnet is cut $k$ times perpendicular to its axis,the length of each piece becomes $\frac{2l}{k+1}$. Here,$k=3$,so the new length $2l' = \frac{2l}{3+1} = \frac{2l}{4}$.The magnetic moment of each piece is $M' = m' 	imes (2l') = \left(\frac{m}{6}ight) 	imes \left(\frac{2l}{4}ight) = \frac{m 	imes 2l}{24} = \frac{M}{24}$.Thus,the pole strength is $\frac{m}{6}$ and the magnetic moment is $\frac{M}{24}$.

If a bar magnet of pole strength $m$ and magnetic moment $M$ is cut equally $5$ times parallel to its axis and again $3$ times perpendicular to its axis,then the pole strength and magnetic moment of each piece are respectively

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